Collatz conjecture: Difference between revisions

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## Proof of Predictability
[[File:Collatz formal.pdf]]
 
To prove the **predictability** of the Collatz conjecture, we demonstrate that for any starting number \( n \), we can predict when the sequence will produce a number smaller than \( n \). This involves analyzing the transformations \( n \to \frac{n}{2} \) (for even numbers) and \( n \to \frac{3n + 1}{2} \) (for odd numbers).
 
### Step 1: Transformation Behavior
 
#### Case 1: \( n \) is even
When \( n \) is even:
\[
n \to \frac{n}{2}
\]
This transformation immediately produces a smaller number because division by 2 reduces the magnitude of any positive integer \( n > 1 \).
 
#### Case 2: \( n \) is odd
When \( n \) is odd:
\[
n \to \frac{3n + 1}{2}
\]
The result may be larger or smaller than \( n \), depending on the value of \( n \). For predictability, we aim to identify **when the sequence will drop below the initial value**.
 
### Step 2: Predicting a Smaller Value
The sequence alternates between odd and even numbers after each transformation:
1. If \( n \) is odd, apply \( n \to \frac{3n + 1}{2} \).
2. If the result is even, repeatedly apply \( n \to \frac{n}{2} \) until another odd number is reached.
 
To predict when the sequence reaches a number smaller than \( n \), consider the "weight" of \( n \), defined by how many times it can be divided by 2 after any application of \( \frac{3n + 1}{2} \).
 
#### Key Observation
For a given number \( n \), the smallest number produced in its sequence depends on the number of times \( n \) (or subsequent terms) can be divided by 2.
 
### Step 3: Formulating the Predictability Rule
To predict when the sequence produces a smaller number, calculate:
\[
k = \text{the highest power of 2 that divides } (n-1)
\]
This works because:
1. The transformation \( n \to \frac{3n + 1}{2} \) introduces a factor of 3 and adds 1.
2. Subtracting 1 from \( n \) aligns the number with the modular behavior of powers of 2, allowing deterministic prediction of when the sequence drops below \( n \).
 
#### Example
* For \( n = 7 \):
  * \( n - 1 = 6 \), and the highest power of 2 dividing 6 is \( 2^1 = 2 \).
  * The sequence for 7 will reach a smaller number after **1 division by 2**.
* For \( n = 15 \):
  * \( n - 1 = 14 \), and the highest power of 2 dividing 14 is \( 2^1 = 2 \).
  * The sequence for 15 will similarly reach a smaller number after **1 division by 2**.
 
### Step 4: Exponential Reduction
Each transformation reduces the size of the number set exponentially:
1. Even numbers are solved immediately.
2. Odd numbers are transformed and alternate between odd/even, with predictable reductions through divisions by 2.
3. The sequence becomes smaller at a predictable rate based on the modular properties of \( n - 1 \).
 
### Conclusion
Predictability is proven because:
1. Every \( n \) eventually produces a smaller number.
2. The specific step where this happens can be calculated directly from \( n - 1 \).

Revision as of 10:48, 20 December 2024

Collatz formal.pdf